SOLUTION: How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to obtain 40 liters of 8% alcohol solution?
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Question 905599: How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to obtain 40 liters of 8% alcohol solution?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
x+y=40,
0.1*x+0.05*y=0.08*40
0.1*x+0.05*y=3.2
x=40-y
0.1*(40-y)+0.05*y=3.2
4-0.1y+0.05*y=3.2
-0.05*y=-0.8
y=16.0 at 5%
x=40-y
x=24.0 at 10%
check
0.1*24.0+0.05*16.0=0.08*40
2.4+0.8=3.2
3.2=3.2
ok
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