SOLUTION: Pure acid is to be added to a 10% solution to obtqin 90L of 14% solution. What amounts of each should be used? How many liters of 100% pure acid should be used to make this solutio
Algebra.Com
Question 904669: Pure acid is to be added to a 10% solution to obtqin 90L of 14% solution. What amounts of each should be used? How many liters of 100% pure acid should be used to make this solution?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The general solution for this kind of problem is thoroughly discussed here:
http://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev
THAT was not the lesson needed;
but THIS was what I meant:
http://www.algebra.com/my/Mixtures%3A-All-in-Symbols.lesson?content_action=show_dev
RELATED QUESTIONS
pure acid is to be added to a 10% acid solution to obtain 90L of 32% soulution. what... (answered by ikleyn,greenestamps)
pure acid is to be added to a 10%acid solution to obtain 90l of 89% solution . what... (answered by vleith)
pure acid is to be added to a 10% acid solution to obtain 90L of 44% solution what... (answered by josgarithmetic)
pure acid is to be added to a 10%acid solution to obtain 90l of 22% solution .
what... (answered by josmiceli)
pure acid is to be added to a 10% acid solution to obtain 90L of 42% solution what... (answered by addingup)
pure acid is to be added to a 10% acid solution to obtain 90l of 75% solution? what... (answered by Fombitz,ewatrrr,josmiceli)
Pure acid is to be added to a 10% acid solution to obtain 90l of 56% solution. What... (answered by stanbon)
pure acid is to be added to a 10% acid solution to obtain 90L of 19% solution. what... (answered by jorel1380)
Pure acid is to be added to a 10% acid solution to obtain 90L of 60% solution. What... (answered by stanbon)