SOLUTION: How many gallons fo a 20% acid solution should be mixed with a 30% acid solution to produce 100 gallons of a 23% solution?

Question 904550: How many gallons fo a 20% acid solution should be mixed with a 30% acid solution to produce 100 gallons of a 23% solution?
Found 2 solutions by ewatrrr, richwmiller:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Set Up
x 30% amount
.30x + .20(100G - x) = .23(100G)
x = .03(100G)/.10 = 30G, the 30% amount. 70G of the 20%
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
a+b=100,
0.2*a+0.3*b=0.23*100
a=100-b
0.2*(100-b)+0.3*b=23
20-0.2b+0.3*b=23
0.1*b=3
b=30
a=100-b
a=70 gal at 20% b=30 gal at 30%
check
0.2*70+0.3*30=0.23*100
14+9=23
23=23
ok

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