SOLUTION: suppose that 50 mL of 25% acid are added to x mL of a 70% acid solution. How much 70% acid should be added to the 25% solution to produce a new solution that is 45% acid? Ive t

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Question 904339: suppose that 50 mL of 25% acid are added to x mL of a 70% acid solution. How much 70% acid should be added to the 25% solution to produce a new solution that is 45% acid?
Ive tried this so far
(50)(0.25)+(x)(0.70)=(x+50)(0.45) but I end up getting that x is 0.025 mL which doesn't seem right.

Answer by josgarithmetic(39616)   (Show Source): You can put this solution on YOUR website!
For thorough help, study this - http://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev

To substitute the given values early,

Just be careful with the arithmetic and the decimal usage, and you should have no real trouble.













, this number of mL


Does that work?

Yes.


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