SOLUTION: You need a 55% alcohol solution. On hand, you have a 45 mL of a 30% alcohol mixture. You also have 60% alcohol mixture. How much of the 60% mixture will you need to add to obtain t

Question 902071: You need a 55% alcohol solution. On hand, you have a 45 mL of a 30% alcohol mixture. You also have 60% alcohol mixture. How much of the 60% mixture will you need to add to obtain the desired solution

Found 2 solutions by josgarithmetic, richwmiller:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The lesson, because the question is one of the most common two-part mixture types - http://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
0.6*x+0.3*45=0.55(45+x)
0.6*x+13.5=24.75+0.55x
0.6x-0.55x=24.75-13.5
0.05x=11.25
x=225 mL of 60% to make 270 mL of 55%
check
0.6*225+0.3*45=0.55(45+225)
135+13.5=0.55(270)
148.5=148.5
ok

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