SOLUTION: A certain contact lens solution is preserved with 0.1% sorbic acid. If a company has made a mistake and produced a solution containing 3% sorbic acid, how much pure water must be a

Question 902011: A certain contact lens solution is preserved with 0.1% sorbic acid. If a company has made a mistake and produced a solution containing 3% sorbic acid, how much pure water must be added to 300 liters of the solution to make the correct percentages in the solution?
Found 2 solutions by josgarithmetic, richwmiller:
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
From a practical point of view, adjusting from 3% to 0.1% only makes sense if the correct amount of sorbic acid was used but much of the water was omitted accidently (like someone forgot to add it).

Understanding that equation is important. If you do not understand that equation, then you may want help for THAT.

If you do understand, then just solve for v.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!

from view of acid
300*0.03=0.01*(300+x)
9=3+0.01*x
9-3=0.01*x
6=0.01*x
x=600
check
300*0.03=0.01*(300+x)
300*0.03=0.01*(900)
9=9
ok
or from view of water
1*y+0.97*300=0.99(300+y)
1*y+291=297+0.99y
1*y-0.99y=297-291
0.01y=6
y=6/0.01
y=600
There are 9 liters of acid 3% of 300 liters
If you add 600 liter of water then you have
9/900=1/100 =1%
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