SOLUTION: How many liters of 60% acid solution must be mixed with a 30% acid solution to get 240 L of a 50% acid solution?
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Question 901863: How many liters of 60% acid solution must be mixed with a 30% acid solution to get 240 L of a 50% acid solution?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
.60x + .30(240L-x) = .50(240L)
x = .20(240L)/.30, amount of 60% solution
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