Hi

     SALT       = SALT

.06x+.22(544L-x)=.13(544L)

I prefer to assign the greater % the  (easier arithmetic)

.22x + .06(544L-x) = .13(544L)

   x = .07(544L)/.16 

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
 

Hi. Here's the textual form of the problem; How many liters of a 6 \% solution of salt should be added to a 22 \% solution in order to obtain 544 liters of a 13 \% solution?

The way I've been setting it up is 

.06x+.022(544-x)=.13

but my final result ends up being -239.36 liters. I have a feeling that one is way wrong, so I'd appreciate any help you'd be willing to offer! 

Thanks in advance- the service you guys provide is amazing. Thank you! 



Let amount of 6% solution to be mixed, be S

Then amount of 22% solution to be mixed = 544 - S

Therefore, .06S + .22(544 – S) = .13(544)

.06S + 119.68 - .22S = 70.72

.06S - .22S = 70.72 – 119.68 

- .16S = - 48.96

S, or amount of 6% solution = , or  L 

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