SOLUTION: a chemist needs 22 liters of a 10% acid solution. how much of a 5% solution should be mixed with a 31% solution to get that?
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Question 899408: a chemist needs 22 liters of a 10% acid solution. how much of a 5% solution should be mixed with a 31% solution to get that?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
.31x + .05(22L-x) = .10(20L)
x = .05(20L/.26
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