Hi

Set UP

.40x + .29(110-x) = .32(110)

       x = .03(110)/.11

 

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
 A chemist needs 110 milliliters of a 32% solution but has only

 29% and 40% solution available. Find how many milliliters of each 

That should be mixed to get the desired solution.

--------

Equation:

active + active = active

0.29x + 0.40(110-x) = 0.32*110

------

29x + 40*110 - 40x = 32*110

-11x = -3*110

x = 10*3 = 30 ml (amt. of 29% solution needed)

110-x = 80 ml (amt. of 40% solution needed)

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Cheers,

Stan H.

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Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
 a+b=110

0.29*a+0.4*b=0.32*110

a=80,   b=30



 

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