SOLUTION: a chemist has two solutions of HNO3. One has a 40% concentration and the other has a 25% concentration. How many liters of each solution must be mixed to obtain 70 liters of a 32%
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Question 894173: a chemist has two solutions of HNO3. One has a 40% concentration and the other has a 25% concentration. How many liters of each solution must be mixed to obtain 70 liters of a 32% solution
x=40%=0.4x
25%=70-x
0.25(70-x)
0.4x+0.25(70-x)=32
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
Maybe the percents are as mass per volume???
If this is the case, then like this to solve:
u = ml of 25%
v = ml of 40%
and .
The concentration equation is simplifiable to .
Solve the system, .
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