Let amount of 12% solution to be mixed be T

Then amount of 20% solution to be mixed = 100 – T

Therefore, we have: .12(T) + .2(100 – T) = .15(100)

.12T + 20 - .2T = 15

.12T - .2T = 15 – 20 

- .08T = - 5

T, or amount of 12% solution to be mixed = , or  L

Amount of 20% solution to be mixed = 100 – 62.5, or  L 

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