SOLUTION: A chemist has three solutions containing a given acid. First solution contains 10% of the acid solution; second solution has 30%, and the third one has 50%. He/she desires to use t

Question 891846: A chemist has three solutions containing a given acid. First solution contains 10% of the acid solution; second solution has 30%, and the third one has 50%. He/she desires to use the three solutions to obtain a mixture of 50 L containing 32% of acid by using twice the 50% solution than 30% solution. How many liters from each solution are to be used?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = liters of the 30% solution used
= liters of the 50% solution used
Let = liters of the 10% solution used
--------------------------------------
= liters of acid in 30% solution
liters of acid in 50% solution
= liters of acid in 10% solution
--------------------------------------
(1)
(2)
(2)
-----------------------
(1)
(1)
(1)
-----------------------
Subtract (2) from (1)
(1)
(2)

and

and, since
(2)
(2)
(2)
(2)
----------------
11 liters of the 30% solution should be used
22 liters of the 50% solution should be used
17 liters of the 10% solution should be used
----------------
check:
(1)
(1)
(1)
(1)
OK

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