SOLUTION: Find the area of the triangle with vertices A(6,-7), B(11,-3) and
C(2,-2).
Algebra.Com
Question 888782: Find the area of the triangle with vertices A(6,-7), B(11,-3) and
C(2,-2).
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the area of the triangle with vertices A(6,-7), B(11,-3) and
C(2,-2).
----------
x: 6 11 +2 +6
y:-7 -3 -2 -7
----------------
Add the diagonal products starting at the upper left.
-18 - 22 - 14 = -54
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Add the diagonal products starting at the lower left.
-77 - 6 - 12 = -95
-----
Area = 1/2 the difference = 41/2
Area = 20.5 sq units
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