SOLUTION: A solution that is 50% alcohol is mixed with a solution that is 40% alcohol in order to make 50 liters of a solution that is 46% alcohol. How many liters of

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Question 880752: A solution that is 50% alcohol is mixed with a solution that is 40% alcohol in order to make
50 liters of a solution that is 46% alcohol. How many liters of the 40% solution and how
many liters of the 50% solution should be used?



Found 2 solutions by mananth, josmiceli:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
percent ---------------- quantity
alcohol I 40.00% ---------------- x liters
alcohol ii 50.00% ------ 50 - x liters
Mixture 46.00% ---------------- 50
Total 50 liters
40.00% x + 50.00% ( 50 - x ) = 46.00% * 50
40 x + 50 ( 50 - x ) = 2300
40 x + 2500 - 50 x = 2300
40 x - 50 x = 2300 - -2500
-10 x = -200
/ -10
x = 20 liters 40.00% alcohol I
30 liters 50.00% alcohol ii

m.ananth@hotmail.ca


Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = liters of 50% solution needed
Let = liters of 40% solution needed
----------------------------------------------
(1)
(2)
-------------------------------------
(2)
(2)
(2)
---------------------------
Multiply both sides of (1) by
and subtract (1) from (2)
(2)
(1)

and, since
(1)
(1)
30 liters of 50% solution is needed
20 liters of 40% solution is needed
check:
(2)
(2)
(2)
(2)
OK

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