SOLUTION: In an alloy of 150 pounds of zinc and copper there are 100 pounds of copper. How much copper must be added so that the alloy may be 10% zinc.

Question 873488: In an alloy of 150 pounds of zinc and copper there are 100 pounds of copper. How much copper must be added so that the alloy may be 10% zinc.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
In an alloy of 150 pounds of zinc and copper there are 100 pounds of copper.
How much copper must be added so that the alloy may be 10% zinc.
:
If there's 100 lb of copper there must be 50 lb zinc, initially
For a mixture to be 10% zinc, it has to be 90% copper
:
Write a percent copper equation
100 + x = .90(150+x)
100 + x = 135 + .9x
x -.9x = 135 - 100
.1x = 35
x = 35/.1
x = 350 lb of copper required
:
Check this; 350 + 150 = 500 lb resulting mixture of copper & zinc
Then .10(500) = 50 of zinc, which is the amt of zinc we have.
And .90(500) = 450 lb of copper
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