SOLUTION: a chemist has one solution that is 60% chlorinated and another that is 40% chlorinated. How much of each solution is needed to make a 100 L solution that is 50% chlorine?

Question 8643: a chemist has one solution that is 60% chlorinated and another that is 40% chlorinated. How much of each solution is needed to make a 100 L solution that is 50% chlorine?

Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Normally this is a word problem that must be worked out with an equation (see my Lesson Plan on Word Problems--Coin and Mixture Problems--Part I). However, there is an intuitive solution to this one if you think about it. You are mixing some 60% and some 40% solutions, trying to obtain a 50% solution, which is exactly halfway between the 60% and the 40%. You will obviously need to mix them half and half. The solution is 50 L of each.

R^2 at SCC
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