SOLUTION: How many ounces of a 20% alcohol solution and a 44% alcohol solution must be combined to obtain 51 ounces of a 28% solution?
Algebra.Com
Question 864196: How many ounces of a 20% alcohol solution and a 44% alcohol solution must be combined to obtain 51 ounces of a 28% solution?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
.20x+.44(51-x)=.28*51
.20x+22.44-.44x=14.28
-.24x=14.28-22.44
-.24x=-8.16
x=-8.16/-.24
x=34 ounces of the 20% SOLUTION IS USED.
51-34=17 OUNCES OF THE 44% SOLUTION IS USED.
PROOF:
.20*34=.44*17=.28851
86.8+7.48=14.28
14.28=14.2
RELATED QUESTIONS
How many ounces of a 16% alcohol solution and a 38% alcohol solution must be combined to... (answered by Alan3354)
How many ounces of a 21% alcohol solution and a 44% alcohol solution must be combined to... (answered by josgarithmetic)
How many ounces of a 14% alcohol solution and a 28% alcohol solution must be combined to... (answered by Alan3354)
how many ounces of 16% alcohol solution and a 28% alcohol solution must be combined to... (answered by josgarithmetic,richwmiller)
How many ounces of a 35% alcohol solution and a 38% alcohol solution must be combined to... (answered by mananth)
how many ounces of a 22% alcohol solution and a 43% alcohol solution must be combined to... (answered by ewatrrr)
How many ounces of a 15% alcohol solution and a 26% alcohol solution must be combined to... (answered by lwsshak3)
how many ounces of a 16% alcohol solution and a 32% alcohol solution must be combined to... (answered by Alan3354)
how many ounces of a 35% alcohol solution and a 41% alcohol solution must be combined to... (answered by Alan3354)