SOLUTION: Chris needs to mix a 20% alcohol solution with a 60% alcohol solution to create 200 millileters of a 54% solution. How many millileters of each solution must Chris use? mililite

Question 858246: Chris needs to mix a 20% alcohol solution with a 60% alcohol solution to create 200 millileters of a 54% solution. How many millileters of each solution must Chris use?
mililiters of 20% solution
mililiters of 60% solution
Answer by ramkikk66(644) (Show Source): You can put this solution on YOUR website!

Let the volume of 20% sol be x
Then volume of 60% sol is 200 - x
Alcohol in 20% sol = 
Alcohol in 60% sol = 
If the final solution is of 54% concentration, it means the volume of alcohol in it
=  
So we have the equation



So he takes 30 ml of 20% alcohol and 170 ml of 60% alcohol
Check:
30 ml contains 30 * 20% = 6 ml of alcohol
170 ml contains 170 * 60% = 102 ml of alcohol
Total alcohol = 6 + 102 = 108 which is 54% of 200 ml. Correct!

:)

RELATED QUESTIONS
Chris needs to mix a 20% fungicide solution with a 40% fungicide solution to create 200... (answered by josgarithmetic)

Katy needs to mix a 10% alcohol solution with 140 milliliters of a 60% alcohol solution... (answered by lwsshak3)

James needs to mix a 10% alcohol solution with a 60% alcohol solution to create 100... (answered by Theo)

Theodore needs to mix a 40% alcohol solution with a 60% alcohol solution to create 100... (answered by josgarithmetic)

Theodore needs to mix a 20% acid solution with a 60% acid solution to create 200... (answered by stanbon)

Monico needs to mix a 20% alcohol solution with a 60% alcohol solution to create 200... (answered by lwsshak3)

mix a 10% acid solution with a 60% acid solution to create 200 millileters of a 52.5%... (answered by josgarithmetic)

Katy needs to mix a 30% acid solution with a 60% acid solution to create 200 millileters... (answered by checkley77)

Kristina needs to mix a 30% methanol solution with a 60% methanol solution to create 200... (answered by mananth)