SOLUTION: A chemist has 40 ounces of a solution that is 30% acid. How many ounces of a 35% acid solution should he add to make a solution that is 33% acid?
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Question 855903: A chemist has 40 ounces of a solution that is 30% acid. How many ounces of a 35% acid solution should he add to make a solution that is 33% acid?
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I tried: 40(30%)+x(35%)=33% but I came up with 1357/7 and that's not the right answer. I really have no clue how to set this problem up correctly.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A chemist has 40 ounces of a solution that is 30% acid
How many ounces of a 35% acid solution should he add to make a solution that is 33% acid?
:
Let x = amt of 35% acid
:
Write a mixture equation using the decimal equiv of the percentages
.30(40) + .35x = .33(x+40)
12 + .35x = .33x + 13.2
.35x - .33x = 13.2 - 12
.02x = 1.2
x = 1.2/.02
x = 60 oz of 35% solution required
;
:
Check this
12 + .35(60) = .33(100)
12 + 21 = 33; confirms our solution
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