SOLUTION: How many gallons of a 24% saline solution (NaCl) must be mixed with 5 gallons of pure water to make a 9% solution?

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Question 853076: How many gallons of a 24% saline solution (NaCl) must be mixed with 5 gallons of pure water to make a 9% solution?
Found 2 solutions by ewatrrr, josgarithmetic:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Let x represent the 24% saline solution (76% water
water = water
.76x + 1.00(5gal) = .91(x + 5gal)
.09(5gal)/.15 = x

Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
The densities may be needed.
24%, about 1.19 g/ml
9%, about 1.07 g/ml
WATER, 1.00 g/ml and 1 gallon = 3.7854 liters

5 gallons of water is liters

The question could be restated as , how many liters of 24% w/vol saline must be mixed with 18.927 liters of water to make 9% w/vol. solution?
Start the solution process assigning variables:
u = volume liters of the 24% w/vol. saline

WRONG--SEE BELOW!___ -------densities seem not to be needed.

Change the result for u back to gallons from the liters.
-
The attempt at unit checking was overdone and created confusion. Since densities were not needed, the more typical setup should simply be:

and this will give liters, which converts to 3 gallons.
RESULT: of 24% w/v saline.

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