SOLUTION: In an experiment, a 100 ml of alcoholic solution must have a 20% alcohol in it. If 40ml of water is added in the solution, how much alcohol must be added, to maintain the 20% alcoh
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Question 847856: In an experiment, a 100 ml of alcoholic solution must have a 20% alcohol in it. If 40ml of water is added in the solution, how much alcohol must be added, to maintain the 20% alcohol solution?
Found 2 solutions by josgarithmetic, lwsshak3:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The concentration of alcohol in the 100 ml. alcohol solution is still unknown. You do not then have a way to find how much water to add to make 20% alcohol.
Assuming percents are vol/vol, and you have 100 ml. of some c percent alcohol, and you want to add 40 ml. of water; AND also some v amount of 100% alcohol to make 20% solution, ...
Amount of pure alcohol =
Amount of solution result =
Equation for adjustments to be 20% alcohol: ;
Simplified:
further simplifiable based on the convenient numbers,
OR
----simplified equation to solve for v or c.
Recheck your problem description for better/more precise problem description or for any missing information omitted from your help request.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
In an experiment, a 100 ml of alcoholic solution must have a 20% alcohol in it. If 40ml of water is added in the solution, how much alcohol must be added, to maintain the 20% alcohol solution?
***
let x=amount of alcohol to add
concentration of original solution=20%=20/100
concentration of new solution=20%=(20+x)/140
20/100=(20+x)/140
2800=2000+100x
100x=800
x=8
amount of alcohol to add=8ml
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