SOLUTION: Find the smallest number that gives a remainder of 1 when divided by 4, a remainder of 2 when divided by 5, and a remainder of 3 when divided by 6?
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Question 847672: Find the smallest number that gives a remainder of 1 when divided by 4, a remainder of 2 when divided by 5, and a remainder of 3 when divided by 6?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
x mod 4=1,
x mod 5=2,
x mod 6=3
x = 3(20n+19),
x= 60+57
117/4 29 +1
117/5 23*5 +2
117/6= 114 + 3
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