SOLUTION: A radiator contains 5 quarts of fluid, 25% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 50% antifreeze?

Question 847174: A radiator contains 5 quarts of fluid, 25% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 50% antifreeze?
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Drain v quarts of the 25% and replace with v quarts of the pure, 100%.

Amount of antifreeze will be: , which is 100 times larger because of using the percents unit. Simplify partway into .

The equation for wanting 50% antifreeze result is:
.
Solve for v.

A next step could be the combined step, ....

quarts
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