SOLUTION: A new edition of a video game cost $60, but its previous version only cost $40. If 15 games are sold for $840, how many copies of the newest game sold?
Algebra.Com
Question 844196: A new edition of a video game cost $60, but its previous version only cost $40. If 15 games are sold for $840, how many copies of the newest game sold?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Maybe a mixture problem but also a linear system problem.
n is how many new
p is how many previous versions
Account for total versions sold:
Account for sales value: which is simplifiable to
SOLVE THE SYSTEM:
----------------------
n+p=15
----------------------
3n+2p=42
----------------------
Choosing Elimination Method, you can use 2n+2p=30 and 3n+2p=42, and subtract first equation from second equation.
and this means
RELATED QUESTIONS
A new edition of a video game costs $60 but it's previous version only costs $40. If 15... (answered by richwmiller)
I need help. I have no idea how to solve this word problem using the five step method. A... (answered by JBarnum)
A video game system and several games are sold for $500. The cost of the games is 3 times (answered by solver91311)
A video game system and several games are sold for $540. The cost of the games is 3 times (answered by TimothyLamb)
A video game system and several games are sold for $552 the cost of the games is three... (answered by TimothyLamb)
a video game system and several games are sold for $504 the cost of the games is 3 times... (answered by brysca)
A video game system and several games are sold for $ 556. The cost of the games is 3... (answered by JoelSchwartz)
a video game system and several games are sold for $564. the cost of the games is 3 times (answered by ikleyn)
a toy store buys video games @ a wholesale price of $18.75.they mark up each game 60%.a... (answered by rfer)