SOLUTION: Joe mixed raisins and nuts. He bought 4 pounds of nuts for a total of $22. The cost per pound of raisins is 60% more than the cost per pound for nuts. Joe bought enough raisins

Question 843829: Joe mixed raisins and nuts. He bought 4 pounds of nuts for a total of $22. The cost per pound of raisins is 60% more than the cost per pound for nuts. Joe bought enough raisins that when he mixed them with the nuts, the mixture had a value of $6.50 per pound. What percent of the mixture, by weight, was raisins?
Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!
Price of the nuts:
22 dollars for 4 pounds.
dollars per pound,
dollars per pound
dollars per pound, nuts.
$5.50 per pound, nuts.

Price of the raisins:
This price is 60% higher than price of the nuts.

$8.80 per pound, raisins.

Mixture Price $6.50 Per Pound.
How much of each was used?
n for nuts
r for raisins.
-
EQUATIONS: , which is arbitrary but convenient;
.
Solve these two simultaneous equations for n and r.

Study this lesson to develop a thorough understanding of this type of mixture problem: http://www.algebra.com/tutors/mixture-price-two-part-both-parts-unknown.lesson?content_action=show_dev
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