Hi,

Let x represent How much pure acid should be mixed

Set Up is:

        Acid = Acid

    | Solve for x

            

                x = 4gal pure acid should be mixed

 

 

Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
 How much pure acid should be mixed with four gallons of a 40% acid solution in order to get a 70% acid solution?

***

let x=amount of pure acid should be mixed

40%*4+100%x=70%(4+x)

1.6+x=2.8+.7x

0.3x=1.2

x=4

amount of pure acid should be mixed=4 gal 

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