SOLUTION: 2000 kg of steel containing 8% nickel is to be made by mixing a steel containing 14% Ni, with another containing 6% nickel.How much of each is needed?

Algebra.Com
Question 830094: 2000 kg of steel containing 8% nickel is to be made by mixing a steel containing 14% Ni, with another containing 6% nickel.How much of each is needed?
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
a+b=2000,
.08*2000=.14a+.06b
a=500., b=1500.

RELATED QUESTIONS

How many kg of a metal containing 20% nickel must be combined with 9 kg of pure nickel to (answered by mananth)
How many liters of a 35% acid solution should be mixed with a 14% solution to obtain 70... (answered by ptaylor)
How many 6 mg of mg of a metal containing 45% nickel must be combined with 6 mg of pure... (answered by checkley77)
How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to (answered by josmiceli)
how many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to (answered by htmentor)
How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to (answered by jorel1380)
How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to (answered by josmiceli)
How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel... (answered by ikleyn)
How many pounds of a metal containing 35% nickel would be needed to melt and mix with... (answered by richwmiller)