SOLUTION: We have 500 ml of soda solution (density = 1.08 g/ml and 8% (m/m) soda).
We need to make a soda solution which contains 15% (m/m) soda.
How much of crystal soda (62.9% (m/m) wa
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Question 828932: We have 500 ml of soda solution (density = 1.08 g/ml and 8% (m/m) soda).
We need to make a soda solution which contains 15% (m/m) soda.
How much of crystal soda (62.9% (m/m) water) do we need to add?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Starter amount of soda solution is 500*1.08 grams, 540 grams of 8% m/m soda.
You want to add some x amount of 62.9% m/m WATER, which is 37.1% SODA, to the 540 grams to get 15% m/m soda. To this extent, we are no longer interested in volumes.
I said this, which was WRONG------------------------------------
Solve for x, the grams of the "Crystal Soda" 62.9% m/m to add.
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I should have said this, much more correct---------------------
Solve for x, the grams of "Crystal Soda", 62.9% m/m water, 37.1% SODA
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One would imagine that Crystal Soda is the name of a concentrated carbonated drink. On the other hand, 8% sodium hydroxide has a density very close to what you gave. 62.9%, concentration of the water, 37.1% m/m of SODA.
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