SOLUTION: one solution is 80% acid and another one is 20 % acid . how much of each solution is needed to mak one hundred galons that is 65 %

Question 825492: one solution is 80% acid and another one is 20 % acid . how much of each solution is needed to mak one hundred galons that is 65 %

Found 2 solutions by TimothyLamb, josgarithmetic:
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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80x + 20y = 65*100
x + y = 100
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put the system of linear equations into standard form
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80x + 20y = 6500
x + y = 100
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copy and paste the above linear system in standard form into this matrix-method solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = 75 gallons of 80%
y = 25 gallons of 20%
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system matrix
80 20
1 1
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inverse of system matrix
0.016666667 -0.33333333
-0.016666667 1.3333333
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determinant of system matrix = 60
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Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
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Solve systems of linear equations up to 4-equations 4-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
See the lesson I wrote:
http://www.algebra.com/my/Mixtures%3A-All-in-Symbols.lesson?content_action=show_dev
'
Or check for this lesson linked in my profile.
"Mixing two concentrations for known amount of mixture"
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