SOLUTION: Pipe A can fill a tank in 6 hours, and pipe B can fill it in 2 hours less time than it takes drainpipe C to empty the tank. With all three pipes open, it takes 3 hours and 20 minut

Algebra.Com
Question 823811: Pipe A can fill a tank in 6 hours, and pipe B can fill it in 2 hours less time than it takes drainpipe C to empty the tank. With all three pipes open, it takes 3 hours and 20 minutes to fill the tank. How long does it take drainpipe C to empty the full tank with pipes A and B closed.
Found 3 solutions by richwmiller, Edwin McCravy, AnlytcPhil:
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
1/6+1/(c-2)-1/c=3/10
c=5
check
1/6+1/3-1/5=3/10
5/30+10/30-6/30=9/30
15-6/30=9/30
ok
or
10/3/6+10/3/(c-2)-10/3/c=1
-10/(3 c)+10/(3 (c-2))+5/9 = 1



Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!

Answer by AnlytcPhil(1806)   (Show Source): You can put this solution on YOUR website!
This is the correct complete solution:

Pipe A can fill a tank in 6 hours,
So Pipe A's tank filling rate is 1 tank per 6 hr or  or 

pipe B can fill it in 2 hours less time than it takes drainpipe C to empty the tank (with pipes A and B closed).
 
Suppose drainpipe C can drain 1 tank in x hours.  Then drainpipe C's "filling"
rate is a negative quantity -1 tank per x hours or  or 
pipe B can fill it in 2 hours less time than it takes drainpipe C to empty the tank.
 
So Pipe B's tank filling rate is 1 tank per x-2 hr or  or 
With all three pipes open, it takes 3 hours and 20 minutes to fill the tank.
3 hours and 20 minutes is  or  hours.  

So A, B, and C's combined filling rate is 1 tank per  hr or  or  or 

So we have this equation:



   

   
Multiply through by LCD = 30x(x-2)

   5x(x-2) + 30x - 30(x-2) = 3·3x(x-2)
5x² - 10x + 30x - 30x + 60 = 9x(x-2)
            5x² - 10x + 60 = 9x² - 18x
                         0 = 4x² - 8x - 60

Divide through by 4      0 = x² - 2x - 15
                         0 = (x - 5)(x + 3)
                             x-5=0;   x+3=0
                               x=5;     x=-3 (ignore)

Aswer: 5 hours

Edwin

RELATED QUESTIONS

Please help me solve this question: Pipe A can fill a tank in 5 h. Pipe B can fill it in... (answered by josgarithmetic,josmiceli)
Pipe A can fill a tank in 5 hours. Pipe B can fill the tank in 2 hours less time than it... (answered by stanbon,ankor@dixie-net.com)
2) Pipe A can fill a tank in 4hr. Pipe B can fill the tank in 9hr less than the time it... (answered by ankor@dixie-net.com)
Please help me solve this question: Pipe A can fill a tank in 5 h. Pipe B can fill it in... (answered by josgarithmetic)
Pipe A can fill a tank in five hours pipe B can fill it in two hours less than it takes... (answered by josgarithmetic,josmiceli,ikleyn)
Pipe A can fill a tank in 4 h. Pipe B can fill the tank in 9 h less than the time it... (answered by josmiceli)
An inlet pipe can fill a tank in 8 hours when the drainpipe is open and in 5 hours when... (answered by richwmiller)
Pipe A can fill a pool in 5 hours. Pipe B can fill it in 2 hours less than it takes Pipe (answered by josmiceli)
Pipe A can fill a tank in 2 hours and Pipe B can fill ii in half the it takes Pipe C to... (answered by ankor@dixie-net.com)