SOLUTION: How many liters of 40% acid solution must be mixed with 10 liters of a 65% acid solution to get a 45% acid solution?
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Question 823038: How many liters of 40% acid solution must be mixed with 10 liters of a 65% acid solution to get a 45% acid solution?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Assign Variables:
v = How many liters of 40% acid
L = 40%, the low concentration of acid
R = 10 liters of 65%, higher concentrated acid
H = 65% the higher concentration acid
T = 45%, the target concentration of acid wanted
{pure amount of acid}/{amount of blend}={resulting concentration}
, which is 100 times larger because direct percents are used;
Equation to solve:
'
Solve for the UNKNOWN variable, v.
Replace all other variables with their given values and compute v.
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