SOLUTION: How many gallons of 65% antifreeze and how many gallons of 20% antifreeze should be mixed to obtain 50 gallons of a 56% mixture of antifreeze? (Hint: Let x represent the number of
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Question 819749: How many gallons of 65% antifreeze and how many gallons of 20% antifreeze should be mixed to obtain 50 gallons of a 56% mixture of antifreeze? (Hint: Let x represent the number of gallons of 65% antifreeze. Then 50 - x represents the amount of 20% antifreeze.)
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
65s + 20w = 56(50)
s + w = 50
w = 50 - s
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65s + 20w = 56(50)
65s + 20(50 - s) = 2800
65s + 1000 - 20s = 2800
45s = 1800
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s = 40 gal
w = 10 gal
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