SOLUTION: How much of a 70%-alcohol solution must be mixed with 50 gallons of a 23%-alcohol solution to obtain a solution that is 60% alcohol?
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Question 815426: How much of a 70%-alcohol solution must be mixed with 50 gallons of a 23%-alcohol solution to obtain a solution that is 60% alcohol?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
.7x+.23*50=.6*(x+50)
0.7x+11.5 = 0.6 x+30.
0.1 x=18.5
x = 185.
since 60 is so close to 70 you know it is going to be a lot
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