SOLUTION: you need to use 3 calculations of drug H containing respectively 50%, 20% and 5% to make 600ml of 10% drug H. how much of the 50% will you use? How much 30% alcohol, 45% alcohol

Question 808325: you need to use 3 calculations of drug H containing respectively 50%, 20% and 5% to make 600ml of 10% drug H. how much of the 50% will you use?
How much 30% alcohol, 45% alcohol. 60% alcohol and 95% alcohol could be mixed to make 200ml of 50% alcohol
These 2 questions how to solve for me
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
you need to use 3 calculations of drug H containing respectively 50%, 20% and 5% to make 600ml of 10% drug H. how much of the 50% will you use?
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You can make 10% using 50% and 5%.
Do it like this one. Only the numbers are different.
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Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use?
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e = amount of 8%
f = amount of 56%
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e+ f = 8 (total solution)
8e + 56f = 20*8 (total saline)
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e+ f = 8
e + 7f = 20
------------ Subtract
-6f = -12
f = 2
e = 6
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How much 30% alcohol, 45% alcohol. 60% alcohol and 95% alcohol could be mixed to make 200ml of 50% alcohol
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To make 50%, you need to mix one higher and one lower concentration, eg, 30% & 60%, 30% & 95%, etc.
See above.
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PS Tutoring is not doing it for you.

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