SOLUTION: You need to use 3 solutions of drug H containing respectively 50%, 20% & 5% to make 600ml of 10% drug H. How much of the 50% will you use?
My own calculation 50% = 55ml
Algebra.Com
Question 808302: You need to use 3 solutions of drug H containing respectively 50%, 20% & 5% to make 600ml of 10% drug H. How much of the 50% will you use?
My own calculation 50% = 55ml
20% = 109ml
5% = 437ml
who helps me to solve it for me step by step
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
You can use 50% and 5%, or 20% and 5%.
There's no reason to use all 3.
======================
Do it like this one. Only the numbers are different.
-----------
Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use?
================
e = amount of 8%
f = amount of 56%
---
e+ f = 8 (total solution)
8e + 56f = 20*8 (total saline)
---
e+ f = 8
e + 7f = 20
------------ Subtract
-6f = -12
f = 2
e = 6
RELATED QUESTIONS
you need to use 3 solutions of drug H containing respectively 50%, 20%, and 5% to make... (answered by josmiceli)
You need to use 3 solutions of drug H containing respectively 50%, 20% and 5% to make... (answered by josgarithmetic)
you need to use 3 calculations of drug H containing respectively 50%, 20% and 5% to make... (answered by Alan3354)
You need to use 3 solutions of drug H containing respectively 50%, 20% and 5% to make... (answered by stanbon)
How much drug would you need to make two onces of a 20%... (answered by solver91311)
A pharmacist has 30% solution of a certain drug and a 12% solution of the same drug. How... (answered by checkley77)
a pharmacist has 20 L of a 10% drug solution. how many liters of 5% drug solution must be (answered by josgarithmetic)
The function D(h)=7e^-0.3h can be used to find the number of milligrams D of a certain... (answered by josgarithmetic)
the function D(h)=7e^-0.3h can be used to find the number of milligrams D of a certain... (answered by josgarithmetic)