SOLUTION: A company that supplies bulk candy to bakeries has one batch of chocolate chips that are 50% dark chocolate and 50% milk chocolate. They have another batch that is 80% dark choc

Question 799074: A company that supplies bulk candy to bakeries
has one batch of chocolate chips that are 50% dark chocolate and
50% milk chocolate. They have another batch that is 80% dark
chocolate and 20% milk chocolate. One of their customers sends
in a rush order for 100 lb of a mix that is 68% dark chocolate.
How many pounds from each batch should be mixed to meet this
order?
Found 2 solutions by stanbon, Finavon:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A company that supplies bulk candy to bakeries
has one batch of chocolate chips that are 50% dark chocolate and
50% milk chocolate. They have another batch that is 80% dark
chocolate and 20% milk chocolate. One of their customers sends
in a rush order for 100 lb of a mix that is 68% dark chocolate.
How many pounds from each batch should be mixed to meet this
order?
--------------
Equation:
dark + dark = dark
0.50x +0.80(100-x) = 0.68*100
--------
50x +80*100 - 80x = 68*100
-30x = -12*100
x = (2/5)100
x = 40 lb (amt. of 50% chips needed)
100-x = 60 lb (amt. of 80% chips needed)
===================
Cheers,
Stan H.
===================
Answer by Finavon(81) (Show Source): You can put this solution on YOUR website!
n lb 50%; gives 50n
(100-n) lb 80% gives 80(100-n)
Total 100lb 68% 6800
6800=50n+8000-80n
30n = 1200
n=40
40 lb 50/50 and 60 lb 80/20
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