SOLUTION: My problem is "Suppose you wish to mix 10% acid solution with 24% acid solution to make 10 liters of 14% acid solution. How many liters of each solution should you use?" So all

Question 798998: My problem is "Suppose you wish to mix 10% acid solution with 24% acid solution to make 10 liters of 14% acid solution. How many liters of each solution should you use?"
So all I can think to do is .1x+.24x=.14(10) then solve for x but that gives me 4.11 and I can't mix two 4 liter solutions to make 10 liters obviously that makes no sense.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
"Suppose you wish to mix 10% acid solution with 24% acid solution to make 10 liters of 14% acid solution.
How many liters of each solution should you use?"
:
Do it this way,
Let x = amt of 24% solution
then total amt is to e 10 l, therefore
(10-x) = amt of 10% solution
:
A simple mixture equation
.24x + .10(10-x) = .14(10)
RELATED QUESTIONS
a 24% acid solution is mixed with a 14% acid solution to form a 19% acid solution. How... (answered by josgarithmetic,Alan3354)

How many liters of pure acid should a chemist mix with 4 liters of a 10% acid solution to (answered by josmiceli)

Mix a solution that is 50% acid with a solution that is 100% water to make 4 liters of a... (answered by brucewill)

A 5% acid solution is mixed with a 9% acid solution. How many ounces of the 5% acid... (answered by stanbon)

A chemist wishes to mix a solution that is 10% acid. She has on hand liters of a 6% acid... (answered by josgarithmetic,greenestamps,MathTherapy,markjames,ikleyn)

How many liters of a 12% acid solution must be mixed with 10 Liters of a 24% Acid... (answered by josgarithmetic)

if you mix 10 liters of 50% acid solution with 30 liters of 20% acid solution, then what... (answered by nerdybill)

Thank you in advance for your help with this problem. How many liters of 60% acid... (answered by scott8148)

Suppose you work in a lab. You need a 15% acid solution for a certain test, but your... (answered by ewatrrr)