SOLUTION: how many liters of a 40% solution must be mixed with 40 liters of a 90% solution to get a 50% solution

SOLUTION: how many liters of a 40% solution must be mixed with 40 liters of a 90% solution to get a 50% solution

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Question 798931: how many liters of a 40% solution must be mixed with 40 liters of a 90% solution to get a 50% solution
Answer by Finavon(81) (Show Source): You can put this solution on YOUR website!
x of 40% 40x
40 of 90% 3600
40+x of 50% (40+x)*50
40x+3600=2000+50x
x=160L

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