SOLUTION: Wilson has a bottle containing 35 millimeters of 15% saline solution and a bottle of 40% saline solution. She wants a 30% solution. How much of the 40% solution must be added to th

Question 798597: Wilson has a bottle containing 35 millimeters of 15% saline solution and a bottle of 40% saline solution. She wants a 30% solution. How much of the 40% solution must be added to the 15% solution so that 30% concentration is created?
Answer by Finavon(81) (Show Source): You can put this solution on YOUR website!
Vol 40%: n
35 @ 15% = 525
n @ 40% = 40n
Total 35+n @ 30% = 525+40n
So
525 + 40n = 30*35 + 30n
Subtracting (30n + 525) gives
10n = 1050-525 = 525
n = 52.5ml
Check :

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