SOLUTION: how much of an alloy that is 20% copper should be mixed with 600 ounces of an alloy that is 60% copper in order to get an alloy that is 30% copper

Question 798463: how much of an alloy that is 20% copper should be mixed with 600 ounces of an alloy that is 60% copper in order to get an alloy that is 30% copper
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
how much of an alloy that is L% copper should be mixed with V ounces of an alloy that is H% copper in order to get an alloy that is T% copper?

Very typical two-part mixture problem.

Let u = ounces of the L% alloy.
L = 20% Cu
T = 30% Cu
H = 60% Cu
V = 600 ounces of the 60% alloy

Solve for u.
Substitute the given values to find the value for u.
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