SOLUTION: how many gallons of a 90% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a mixture that is 80% antifreeze
Algebra.Com
Question 796685: how many gallons of a 90% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a mixture that is 80% antifreeze
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
how many gallons of a 90% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a mixture that is 80% antifreeze
***
let x=amount of 90% solution to mix
70-x=amount of 20% solution to mix
..
90%x+20%(70-x)=80%*70
.9x+14-.2x=56
.7x=42
x=60
70-x=10
..
amount of 90% solution to mix=60 gal
amount of 20% solution to mix=10 gal
RELATED QUESTIONS
How many gallons of 70% antifreeze solution must be mixed with 90 gallons of 25%... (answered by oberobic)
How many gallons of 80% antifreeze solution must be mixed with 90 gallons of 25%... (answered by Fombitz)
how many gallons of 50% antifreeze solution must be mixed with 90 gallons of 20%... (answered by josgarithmetic)
How many gallons of a 70% antifreeze solution must be mixed with 90 gallons of 25%... (answered by richwmiller)
How many gallons of 80% antifreeze solution must be mixed with 90 gallons of 15%... (answered by lwsshak3)
how many gallons of a 70% antifreeze solution must be mixed with 90 gallons of 25%... (answered by mananth)
how many gallons of a 90 antifreeze solution must be mixed with 100 gallons of 25... (answered by stanbon)
How many gallons of a 70% antifreeze solution must be mixed with 70 gallons of 10%... (answered by stanbon)
How many gallons of a 70% antifreeze solution must be mixed with 70 gallons of 10%... (answered by solver91311)