SOLUTION: A baseball is thrown straight upward with an initial speed 64ft/sec. The number of feet, s, above the ground after t seconds is given by the equation, s=-16t^2+64t.
a)When will
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Question 795557: A baseball is thrown straight upward with an initial speed 64ft/sec. The number of feet, s, above the ground after t seconds is given by the equation, s=-16t^2+64t.
a)When will the baseball be 48 ft above the ground?
b)When will it hit the ground?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
s=-16t^2+64t.
a)When will the baseball be 48 ft above the ground?
s=-16t^2+64t = 48
Solve for t
----------------
b)When will it hit the ground?
s=-16t^2+64t = 0
Solve for t
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