SOLUTION: A certain automobile cooling system contains 11.0 liters of coolant that is 15% antifreeze. How man liters of mixture must be removed so that, when it is replaced with pure antifre
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Question 793100: A certain automobile cooling system contains 11.0 liters of coolant that is 15% antifreeze. How man liters of mixture must be removed so that, when it is replaced with pure antifreeze, a mixture of 25% antifreeze will result
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A certain automobile cooling system contains 11.0 liters of coolant that is 15% antifreeze. How man liters of mixture must be removed so that, when it is replaced with pure antifreeze, a mixture of 25% antifreeze will result.
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Equation:
anti - anti + anti = anti
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0.15*11 - 0.15x + 1*x = 0.25*11
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15*11 - 15x + 100x = 25*11
85x = 10*11
x = 1.2941 liters (amt of antifreeze to remove and replace)
Cheers,
Stan H.
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Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
L:et = liters of mixture to be removed
and replaced with pure antifreeze
----------------------------
= liters of pure antifreeze
in liters of mixture
-----------------------
liters of pure antifreeze in
original mixture
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Note that you end up with the same number
of liters that you started with
-------------
liters
-------------------
check answer:
OK
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