SOLUTION: How many pounds of a chicken feed that sells for $5 a lb. must be mixed with 400 pounds of a feed
that sells for $8 a lb.to make a chicken feed that sells for $7.50 a lb.? 5x+8x/4
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Question 789692: How many pounds of a chicken feed that sells for $5 a lb. must be mixed with 400 pounds of a feed
that sells for $8 a lb.to make a chicken feed that sells for $7.50 a lb.? 5x+8x/400=7.50
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Pay closer attention to cost and pounds. This is a mixture problem and the concentration is DOLLARS per POUND. Your target is 7.50 dollars per pound.
Using the variable choices as you tried,
x = pounds of the lower priced feed
y = pounds of the higher priced feed, but you do NOT need this as variable.
Already you were given to start with 400 pounds of the 8$/pound feed.
SOLVE FOR x.
SOME INSTRUCTION---------------------------------------------
DEVELOP THE EQUATION:
{COST OF MIXTURE}/{AMOUNT OF MIXTURE}={PRICE FOR MIXTURE}
You know the amount of the $8/pound chicken feed, 400 pounds.
The amount of the $5/pound feed is unknown variable, x.
Cost for the mixture is 5x+8*400 dollars.
The amount of mixture is a variable expression, x+400.
You want the PRICE of the mixture to be 7.50 dollars per pound.
Put this altogether and make .
You clear the "fraction" by doing something to BOTH sides of the equation. This means, multiply left and right sides by (x+400); simplify if you wish. You are initially relying on the idea, being equivalent to , which would be . (Generalizing here so you see the rule).
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