SOLUTION: You need 325 mL of a 5% alcohol solution. On hand, you have a 25% alcohol mixture. How much of the 25% alcohol mixture and pure water will you need to obtain the desired solution?

Question 788849: You need 325 mL of a 5% alcohol solution. On hand, you have a 25% alcohol mixture. How much of the 25% alcohol mixture and pure water will you need to obtain the desired solution?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
{pure alcohol content}/{total amount of solution}={Target Concentration}

u = amount of the water which is 0% alcohol
v = amount of the 25% alcohol

and

and substitute into the rational equation.

mL.

Steps can vary. Some people's steps may be more efficient than shown here. Using factors and making more steps was easier here to avoid using separate computations on paper for simplifications.
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