SOLUTION: Pure acid is to be added to a 10% solution to obtain 27 liters of a 20% acid solution. What amounts of each should be used? What is my x and y and how do I come up with 2 syst

Question 788611: Pure acid is to be added to a 10% solution to obtain 27 liters of a 20% acid solution. What amounts of each should be used?

What is my x and y and how do I come up with 2 system of equations?
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
= amount of acid added (in liters)
= amount of 10% solution you start with (in liters)

One equation is the balancing of total amounts (in liters)

The other equation is the balancing of the amount of pure acid:
<--><-->
Since you start with liters of 10% acid, you are starting with 10% of liters of pure acid in that solution, or

You add liters of pure acid, and end up with 27 liters of a 20% acid solution that must contain 20% of 27 liters of pure acid, or

Your system could be
or

NOTE:
As a chemist, I find this kind of problem offensively wrong in more ways than I care to count, but since I can't beat them, I may as well join them and pretend that it makes sense.
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