SOLUTION: A 90% acid solution is diluted with water to make a solution of 60% acid. When liters of water is added to dilute it again, the solution becomes 40% acid. How much water is added t

Question 788263: A 90% acid solution is diluted with water to make a solution of 60% acid. When liters of water is added to dilute it again, the solution becomes 40% acid. How much water is added to the solution on the first instance? How much 90% acid was available at the start?
thank you very much~! :)
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
You need more information. The description is incomplete.

Let f=how much volume of 90% acid
Let y=how much water to add to get 60% acid.

liters of water

The second dilution now starts with (f+f/2) liters of 60% acid.
You want now to dilute to 40% acid.
Let x=volume of water to add for diluting to 40%.

Solve for x.
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