SOLUTION: One jar contains 5/6 alcohol and another 8/9 alcohol. How many liters taken from each jar are required to fill a third jar with a capacity of 24 liters so that the mixture will be

Question 785147: One jar contains 5/6 alcohol and another 8/9 alcohol. How many liters taken from each jar are required to fill a third jar with a capacity of 24 liters so that the mixture will be 7/8 alcohol?
Answer by harpazo(655) (Show Source): You can put this solution on YOUR website!

Here is another method:
Let x = litres of alcohol taken from first jar.
Let y = litres of alcohol taken from second jar.
We will need two equations to get value of x and y.
So first equation is our quantity constraint, i.e., we just need total 24 litres.
x + y = 24
Next equation comes from final composition of alcohol.
5x/6 + 8y/9 = 7*24/8
Solving these two, you get
x=6
y=18
Hope it helps:)
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