SOLUTION: What quantity of a 55% acid solution must be mixed with a 45% solution to produce 600 mL of a 50% solution?

Question 784649: What quantity of a 55% acid solution must be mixed with a 45% solution to produce 600 mL of a 50% solution?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
ASSIGN VARIABLES TO ALL QUANTITIES
L, the lower concentration of available material, 45%
H, the higher concentration of available material, 55%
T, the target concentration of resulting mixture, 50%
M, the amount of resulting mixture, 600 ml.
x, the amount of lower concentrated material to use, unknown
y, the amount of higher concentrated material to use, unknown

EQUATION
and

, and since the two differences here would both be negative,
we can multiply by (-1)/(-1),

After using that formula, you can simply use

Substitute the necessary values and compute x and y.
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